\int \sqrt{x\sqrt{x\sqrt{x\sqrt{...}}}}\;dx= A.    \(x+C\)
B.   \(\frac1{\sqrt x}+C\)
C.   \(\sqrt x+C\)
D.   \(\frac12x+C\)
E.   \(\frac12x^2+C\)
    A    B    C    D    E

[ 6-A259 - op net sinds 21.7.2026-(E)-22.7.2026 ]

Translation in   E N G L I S H

See above

Oplossing - Solution

\inline\\Stel\;\;y=\sqrt{x\sqrt{x\sqrt{x\sqrt{...}}}}\;\;dan\;\;is\\ y=\sqrt{x\cdot y}\;\Rightarrow\;y^2=xy\;\Rightarrow\;y=x\\ \int x\:dx=\frac{x^2}{2}+C

GWB