Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

$\displaystyle\lim_{x\to\,2}\;\frac{\ln\frac{x^2}{4}}{x^3-8}=$	A. \(\frac12\)
B. \(\frac14\)
C. \(\frac16\)
D. \(\frac18\)
E. \(\frac1{12}\)

$\displaystyle\lim_{x\to\,2}\;\frac{\ln\frac{x^2}{4}}{x^3-8}\left(=\frac00\right)\overset{H}{=}\lim_{x\to\,2}\;\frac{\frac{4}{x^2}.\frac{2x}{4}}{3x^2}=\lim_{x\to\,2}\;\frac{\frac2x}{3x^2}=\lim_{x\to\,2}\;\frac{2}{3x^3}=\frac{2}{3.8}=\frac{1}{12}$

^{gricha - vA149 - 15.3.2026}