Wiskunde Multiple Choice Vraag

$\displaystyle\lim_{x\to\,0}\:\frac{e^{-x}+x-2}{x^2}=$	A. 0
	B.
	C. 1
	D.
	E.

[ 6-A066 - op net sinds 15.9.2025-(E)-12.4.2026 ]

$\displaystyle\lim_{x\to\,0}\:\frac{e^{-x}+x-2}{x^2}=$	A. 0
	B.
	C. 1
	D.
	E.

$\displaystyle\lim_{x\to\,0}\:\frac{e^{-x}+x-2}{x^2}=\frac{e^0+0-2}{0^2}=\frac{-1}{+0}=-\infty$

^{gricha - vA066 - 15.9.2025}

GWB