In welke rij staan de breuken in stijgende volgorde ? A.  \(\large\boldsymbol{\frac{2}{3},\;\frac{3}{4},\;\frac{7}{12} }\)
B.  \(\large\boldsymbol{\frac{2}{3},\;\frac{7}{12},\;\frac{3}{4} }\)
C.  \(\large\boldsymbol{\frac{7}{12},\;\frac{2}{3},\;\frac{3}{4} }\)
D.  \(\large\boldsymbol{\frac{7}{12},\;\frac{3}{4},\;\frac{2}{3} }\)
E.  \(\large\boldsymbol{\frac{3}{4},\;\frac{2}{3},\;\frac{7}{12} }\)
A    B    C    D    E

[ 1-9181 - op net sinds 22.10.2018-(E)-2.11.2023 ]

Translation in   E N G L I S H

In which row are
the fractions
in ascending order ? 		A.   \(\boldsymbol{\frac{2}{3},\;\frac{3}{4},\;\frac{7}{12} }\)
B.   \(\boldsymbol{\frac{2}{3},\;\frac{7}{12},\;\frac{3}{4} }\)
C.   \(\boldsymbol{\frac{7}{12},\;\frac{2}{3},\;\frac{3}{4} }\)
D.   \(\boldsymbol{\frac{7}{12},\;\frac{3}{4},\;\frac{2}{3} }\)
E.   \(\boldsymbol{\frac{3}{4},\;\frac{2}{3},\;\frac{7}{12} }\)

Oplossing - Solution

Zet de breuken eerst allemaal op noemer 12 :
\(\:\frac {8}{12} \;,\; \:\frac {9}{12} \;,\; \:\frac {7}{12} \\ \:\frac {8}{12} \;,\; \:\frac {7}{12} \;,\; \:\frac {9}{12} \\ \:\frac {7}{12} \;,\; \:\frac {8}{12} \;,\; \:\frac {9}{12} \\ \:\frac {7}{12} \;,\; \:\frac {9}{12} \;,\; \:\frac {8}{12} \\ \:\frac {9}{12} \;,\; \:\frac {8}{12} \;,\; \:\frac {7}{12} \\ \)
Rekening houdend met de mintekens kunnen we nu concluderen dat C het antwoord is.
GWB