Welk geordend drietal is GEEN oplossing van de vergelijking
x² + y² + z²
= xyz + x + y + z + 2
A. (1,2,3)
B. (0,1,2)
C. (–1,0,1)
D. (0,0,–1)
E. (3,6,10)
F. (2,3,6)
[ 5-8885 - op net sinds 23.5.2024-(E)-26.7.2024 ]
Translation in E N G L I S H
IN CONSTRUCTION
Oplossing - Solution
1²+2²+3² = 1+4+9=14
0²+1²+2² = 1+4=5
1 + 0 + 1 = 2
(–1)² = 1
3²+6²+10²=9+36+100=
145
4 + 9 + 36 = 49
A
B
C
D
E
F
1.2.3+1+2+3+2 = 6+8 = 14
0.1.2+0+1+2+2 = 0+5 = 5
0 –1+1+2 = 2
0 –1 + 2 = 1
3.6.10+3+6+10+2 = 180+21 =
201
2.3.6+2+3+6+2=36+13 = 49
