\(\int_{0}^{\pi} x.f(\sin x)\; dx=\) A.  \(x\cdot \int_{0}^{\pi }f \left ( \sin\: x \right )\: dx\)
B.  \(\pi \cdot \int_{0}^{\pi }f \left ( \sin\: x \right )\: dx\)
C.  \(2\pi \cdot \int_{0}^{\pi }f \left ( \sin\: x \right )\: dx\)
D.  \(\frac{\pi}{2} \cdot \int_{0}^{\pi }f \left ( \sin\: x \right )\: dx\)
E.  \(\int_{0}^{\pi }f \left ( \cos\: x \right )\: dx\)
A    B    C    D    E

[ 6-8728 - op net sinds 5.4.2021-(E)-16.10.2026 ]

Translation in   E N G L I S H

see above

Oplossing - Solution

\(I=\int_{0}^{\pi }\left [x\! \cdot f\left (\sin\: x \right ) \right ]dx \\ Stel \; x=\pi -t \; \Rightarrow \; dx=\!-dt \\ {\color{Yellow} .}\qquad \qquad \qquad \qquad x=0\;\; k.o.m.\; \; t=\pi \\ {\color{Yellow} .}\qquad \qquad \qquad \qquad x=\pi \;\; k.o.m.\; \; t=0 \\ I=\int_{\pi }^{0} \left [(\pi -t).f(\sin\: t) \right ]\cdot (-dt)\\ = -\pi \int_{\pi }^{0}f(\sin\: t)dt+\int_{\pi }^{0}\left [t\cdot f(sin\: t) \right ]dt\\ =\pi \int_{0}^{\pi }f(\sin\: t)\: dt - \int_{0}^{\pi }\left [ t\cdot f(\sin\: t) \right ]dt\\ \Rightarrow I=\pi \int_{0}^{\pi }f(\sin\: t)\: dt\: -\: I \\ \Rightarrow I=\frac{\pi }{2}\int_{0}^{\pi }f(\sin\: t)\: dt={\color{Red} (!)\: }=\frac{\pi }{2}\int_{0}^{\pi }f(\sin\: x)\: dx\)
gricha