Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

$https://latex.codecogs.com/png.image?\dpi{110}\frac{\mathrm{d} }{\mathrm{d} x}\int_{0}^{2x}\cos t \; dt$ ook geschreven als $https://latex.codecogs.com/png.image?\dpi{110}\mathbf{D_x}\; \int_{0}^{2x}\cos t \; dt$ is gelijk aan	A. (cos 2x) − 1
	B. cos 2x
	C. sin 2x
	D. 2.sin 2x
	E. 2.cos 2x

[ 6-8139 - op net sinds 3.1.2018-(E)-3.11.2023 ]

Translation in E N G L I S H

$\frac{\mathrm{d} }{\mathrm{d} x}\int_{0}^{2x}\cos t \; dt$ also written as $\mathbf{D_x}\; \int_{0}^{2x}\cos t \; dt$ is equal to	A. (cos 2x) − 1
	B. cos 2x
	C. sin 2x
	D. 2.sin 2x
	E. 2.cos 2x

Oplossing - Solution

$https://latex.codecogs.com/png.image?\dpi{110}\\\mathbf{D_x}\; \int_{0}^{2x}\cos t \; dt=\mathbf{D_x}\;\left [ \sin x \right ]_{0}^{2x}=\mathbf{D_x}\;\left [ \sin 2x - \sin 0 \right ]=\mathbf{D_x}\;\sin 2x=2.\cos 2x$