Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

$https://latex.codecogs.com/png.image?\dpi{110}\tan \frac x2 =$	A. $\boldsymbol{\frac {\sin x} {1+\,\cos x} }$
	B. $\boldsymbol{\frac {\cos x} {1+\,\sin x} }$
	C. $\boldsymbol{\frac {\sin x} {1-\,\cos x} }$
	D. $\boldsymbol{\frac {\cos x} {1-\,\sin x} }$
	E. $\boldsymbol{\frac {1-\,\cos x} {\sin x} }$

[ 5-7703 - op net sinds 15.4.2023-(E)-3.11.2023 ]

Translation in E N G L I S H

See above

Oplossing - Solution

$https://latex.codecogs.com/png.image?\dpi{110}\tan \frac x2 =\frac{\sin \frac x2}{\cos \frac x2}=\frac{2\sin \frac x2 \cos\frac x2}{2\cos^2 \frac x2}=\frac{\sin x}{1+\cos x}$
(Gebruik gemaakt van de formule 1 + cos 2α = 2 cos²α )

$https://latex.codecogs.com/png.image?\dpi{110}\tan \frac x2 =$	A. \(\boldsymbol{\frac {\sin x} {1+\,\cos x} }\)
	B. \(\boldsymbol{\frac {\cos x} {1+\,\sin x} }\)
	C. \(\boldsymbol{\frac {\sin x} {1-\,\cos x} }\)
	D. \(\boldsymbol{\frac {\cos x} {1-\,\sin x} }\)
	E. \(\boldsymbol{\frac {1-\,\cos x} {\sin x} }\)