Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

De afgeleide $https://latex.codecogs.com/png.image?\dpi{110}D\; \frac{1-x}{1+x}$ is gelijk aan	A. − 1
	B. $\large\boldsymbol{\frac {-1} {(1\,+\,x)^2} }$
	C. $\large\boldsymbol{\frac {2} {(1\,+\,x)^2} }$
	D. $\large\boldsymbol{\frac {-2} {(1\,+\,x)^2} }$
	E. $\large\boldsymbol{\frac {2x\,-\,2} {(1\,-\,x)^2} }$

[ 5-7445 - op net sinds 3.4.2020-()-4.11.2023 ]

Translation in E N G L I S H

IN CONSTRUCTION	A.
	B.
	C.
	D.
	E.

Oplossing - Solution

$\large\textbf{D}\; \frac{1-x}{1+x}=\frac{\left [ \textbf{D}(1-x)\right ].(1+x)-(1-x).\textbf{D}(1+x) }{(1+x)^2}\\=\frac{-1.(1+x)-(1-x).1}{(1+x)^2} =\frac{-1-x-1-x}{(1+x)^2}=\frac{-2}{(1+x)^2} $

De afgeleide $https://latex.codecogs.com/png.image?\dpi{110}D\; \frac{1-x}{1+x}$ is gelijk aan	A. − 1
	B. \(\large\boldsymbol{\frac {-1} {(1\,+\,x)^2} }\)
	C. \(\large\boldsymbol{\frac {2} {(1\,+\,x)^2} }\)
	D. \(\large\boldsymbol{\frac {-2} {(1\,+\,x)^2} }\)
	E. \(\large\boldsymbol{\frac {2x\,-\,2} {(1\,-\,x)^2} }\)