Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

$https://latex.codecogs.com/png.image?\dpi{110}\frac{\sqrt{21}+\sqrt{6}}{\sqrt 3}$ is gelijk aan	A. \(\sqrt2+\sqrt7\)
B. \(\sqrt7+\sqrt6\)
C. 3
D. 9
E. \(\sqrt{21}+\sqrt2\)

$https://latex.codecogs.com/png.image?\dpi{110}\frac{\sqrt{21}+\sqrt{6}}{\sqrt 3}$ is equal to	A. $\sqrt2+\sqrt7$
	B. $\sqrt7+\sqrt6$
	C. 3
	D. 9
	E. $\sqrt{21}+\sqrt2$

1^ste manier :
$\large\frac{\sqrt{21}+\sqrt{6}}{\sqrt 3}=\frac{\sqrt{21}}{\sqrt3}+\frac{\sqrt6}{\sqrt3}=\sqrt7+\sqrt2$
2^de manier :
$\\\frac{\sqrt{21}+\sqrt{6}}{\sqrt 3}=\frac{(\sqrt{21}+\sqrt6)\sqrt3}{\sqrt3\sqrt3}=\frac{\sqrt{21}.\sqrt3+\sqrt6.\sqrt3}{3}=\frac{\sqrt7.\sqrt3.\sqrt3+\sqrt2.\sqrt3.\sqrt3}{3}\\=\frac{3\sqrt7+3\sqrt2}{3}=\sqrt7+\sqrt2$
3^de manier :
$\large\frac{\sqrt{21}+\sqrt{6}}{\sqrt 3}=\frac{\sqrt{7.3}+\sqrt{2.3}}{\sqrt3}=\frac{\sqrt7\sqrt3+\sqrt2\sqrt3}{\sqrt3}=\frac{(\sqrt7+\sqrt2)\sqrt3}{\sqrt3}=\sqrt7+\sqrt2$