D = 4 + 16 = 20 = 4 .5
Er zijn dus twee wortels (oplossingen),
namelijk x1,2 =
(2 ± 2
) = 1 ±
|
Eén van de oplossingen van de vierkantsvergelijking x2 − 2x − 4 = 0 is |
A. \(\boldsymbol{1 + \sqrt 5}\) |
|---|---|
| B. \(\boldsymbol{2 + \sqrt 5}\) | |
| C. \(\boldsymbol{1 + 2\sqrt 5}\) | |
| D. \(\boldsymbol{2\sqrt 5}\) | |
| E. \(\boldsymbol{\sqrt 5}\) |
[ 3,4-6791 - op net sinds 5.1.12-(E)-4.11.2024 ]
|
One of the solutions of the equation x2 − 2x − 4 = 0 is |
A. \(\boldsymbol{1 + \sqrt 5}\) |
|---|---|
| B. \(\boldsymbol{2 + \sqrt 5}\) | |
| C. \(\boldsymbol{1 + 2\sqrt 5}\) | |
| D. \(\boldsymbol{2\sqrt 5}\) | |
| E. \(\boldsymbol{\sqrt 5}\) |
(2 ± 2) = 1 ±
