Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

$\lim_{x \to 2 }\; \frac {\frac 4x -2} {2-x}$	A. 1
	B. 2
	C. 0
	D. ∞
	E. a negative number

$https://latex.codecogs.com/png.image?\dpi{110}\displaystyle \lim_{x \to 2}\:\frac{\frac 4x-2}{2-x}=\displaystyle \lim_{x \to 2}\:\frac{\frac{4-2x}{x}}{2-x}=\displaystyle \lim_{x \to 2}\:\frac{4-2x}{x(2-x)}=\displaystyle \lim_{x \to 2}\:\frac{2(2-x)}{x(2-x)}=\displaystyle \lim_{x \to 2}\:\frac 2x = \frac22=...$