De oplossing van de exponentiële vergelijking
2x+1 + 2x+2 + 2x+3 + 2x+4 + 2x+5 = 5x+1 + 5x+2 + 5x+3
is
A.       1
B.     − 1
C.       2
D.     − 2
E.   een irrationaal getal
A    B    C    D    E

[ 6-5571 - op net sinds 10.12.13-(E)-8.11.2023 ]

Translation in   E N G L I S H

What  is  the  solution  of  the  equation

2x+1 + 2x+2 + 2x+3 + 2x+4 + 2x+5 = 5x+1 + 5x+2 + 5x+3
A.    1
B.    − 1
C.    2
D.    − 2
E.  an irrational number

Oplossing - Solution

  2x+1 + 2x+2 + 2x+3 + 2x+4 + 2x+5 = 5x+1 + 5x+2 + 5x+3
⇔ 2.2x + 4.2x + 8.2x + 16.2x + 32.2x = 5.5x + 25.5x + 125.5x
⇔ 2x(2 + 4 + 8 + 16 + 32) = 5x(5 + 25 + 125)
⇔ 2x.62 = 5x.155     / : 31
⇔ 2x.2 = 5x.5
⇔ 2 / 5 = 5x / 2x
⇔ 2 / 5 = (2 / 5)−x
⇔ x = ...
gricha