Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

$https://latex.codecogs.com/png.image?\large \dpi{110}\frac{1}{(1+i)^2}+\frac{1}{(1-i)^2}$ is gelijk aan	A. \(\small \boldsymbol{ 0 }\)
	B. \(\boldsymbol{ \frac 12 }\)
	C. \(\boldsymbol{ -\,\frac {1} {2i} }\)
	D. \(\boldsymbol{ \frac {1} {2\,+\,2i} }\)
	E. \(\boldsymbol{ \frac 25 }\)
	F. \(\boldsymbol{ \frac {2} {1\,+\,i} }\)

[ 5-5506 - op net sinds 4-7.12-(E)-30.10.2023 ]

Translation in E N G L I S H

$https://latex.codecogs.com/png.image?\large \dpi{110}\frac{1}{(1+i)^2}+\frac{1}{(1-i)^2}$ is equal to	A. \(\small \boldsymbol{ 0 }\)
	B. \(\boldsymbol{ \frac 12 }\)
	C. \(\boldsymbol{ -\,\frac {1} {2i} }\)
	D. \(\boldsymbol{ \frac {1} {2\,+\,2i} }\)
	E. \(\boldsymbol{ \frac 25 }\)
	F. \(\boldsymbol{ \frac {2} {1\,+\,i} }\)

Oplossing - Solution

$\bg_white \frac{1}{(1+i)^2}+\frac{1}{(1-i)^2}=\frac{1}{2i}+\frac{1}{-2i}=0$

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