1opa + 1opa
is gelijk
aan
A.  \( \frac {2} {a} \)
B.  \((\frac {1} {a})^2 \)
C.  \( \frac {2a} {a} \)
D.  \( \frac {2} {a+a} \)
E.  \( \frac {1} {2a} \)
A    B    C    D    E

[ B-5164 - op net sinds 9.6.2020-(E)-24.10.2023 ]

Translation in   E N G L I S H

1opa + 1opa
is equal to
A.   \( \frac {2} {a} \)
B.   \((\frac {1} {a})^2 \)
C.   \( \frac {2a} {a} \)
D.   \( \frac {2} {a+a} \)
E.   \( \frac {1} {2a} \)

Oplossing - Solution

gricha