Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

In een driehoek met hoeken A, B en C is $https://latex.codecogs.com/png.image?\dpi{110}\cos\frac{A+B}{2}$ gelijk aan	A. \(\boldsymbol{\sin \frac {A\,-\,B} {2} }\)
	B. \(\boldsymbol{\sin \frac {B\,-\,A} {2} }\)
	C. \(\boldsymbol{\sin \frac {A} {2} }\)
	D. \(\boldsymbol{\sin \frac {A\,-\,C} {2} }\)
	E. \(\boldsymbol{\sin \frac {C\,-\,A} {2} }\)

[ 4-4984 - op net sinds 28.9.2019-(E)-2.11.2024 ]

Translation in E N G L I S H

In a triangle with angles A, B, C is $https://latex.codecogs.com/png.image?\dpi{110}\cos\frac{A+B}{2}$ equal to	A. \(\boldsymbol{\sin \frac {A\,-\,B} {2} }\)
	B. \(\boldsymbol{\sin \frac {B\,-\,A} {2} }\)
	C. \(\boldsymbol{\sin \frac {A} {2} }\)
	D. \(\boldsymbol{\sin \frac {A\,-\,C} {2} }\)
	E. \(\boldsymbol{\sin \frac {C\,-\,A} {2} }\)

Oplossing - Solution

cos

1/2

(B + C) = cos 1/2

1/2

(180° − A) = cos (90° − 1/2

1/2

A) = sin

1/2

A

gricha