sin x + sin(x + 90°) + sin(x + 180°) + sin(x + 270°) is gelijk aan |
A. 0 |
---|---|
B. 2 sin x | |
C. 2 cos x | |
D. − 2 sin x | |
E. − 2 cos x |
[ 4,5-4945 - op net sinds 6.12.09-(E)-30.10.2023 ]
sin x + sin(x + 90°) + sin(x + 180°) + sin(x + 270°) is equal to |
A. 0 |
---|---|
B. 2 sin x | |
C. 2 cos x | |
D. − 2 sin x | |
E. − 2 cos x |