Uit
sinx.cosx + sin 2x = 1
volgt dat
sin 2x   gelijk is aan
A.   \(1\)
B.   \(2\)
C.   \(\frac13\)
D.   \(\frac23\)
E.   \(\frac12\)
A    B    C    D    E

[ 5-4912 - op net sinds 15.11.13-(E)-13.6.2025 ]

Translation in   E N G L I S H

Knowing that
sinx.cosx + sin 2x = 1
you can conclude that
sin 2x   equals
A.   \(1\)
B.   \(2\)
C.   \(\frac13\)
D.   \(\frac23\)
E.   \(\frac12\)

Oplossing - Solution

sinx.cosx + sin 2x = 1
1op2.2.sinx.cosx + sin 2x = 1
  1op2.sin 2x + sin 2x = 1
    3op2.sin 2x = 1
      sin 2x = 2op3