Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

$https://latex.codecogs.com/png.image?\dpi{110}\displaystyle \lim_{{x \to \frac{3\pi}{2}}}\; \frac {1\,+\:\sin x}{\cos^2x}$ is gelijk aan	A. 1
	B. 2
	C.
	D. 0
	E.
	F.

[ 5-4546 - op net sinds 25.7.2020-(E)-15.11.2024 ]

Translation in E N G L I S H

$\displaystyle \lim_{{x \to \frac{3\pi}{2}}}\; \frac {1\,+\:\sin x}{\cos^2x}$ is equal to	A. 1
	B. 2
	C.
	D. 0
	E.
	F. ∞

Oplossing - Solution

$https://latex.codecogs.com/png.image?\dpi{110}\displaystyle \lim_{{x \to \frac{3\pi}{2}}}\; \frac {1\,+\:\sin x}{\cos^2x}=\displaystyle \lim_{{x \to \frac{3\pi}{2}}}\; \frac{1+\sin x}{1-\sin^2x} =\displaystyle \lim_{{x \to \frac{3\pi}{2}}}\; \frac{1}{1-\sin x}=\frac12$