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Van een Rekenkundige Rij t1, t2, ... met verschil v = 5, is s100 − s99 = 1000. De waarde van de term t101 is |
A. 1000 |
|---|---|
| B. 1005 | |
| C. 1010 | |
| D. 1500 | |
| E. minder dan 1000 |
[ 4,6-4275 - op net sinds 24.9.11-(E)-26.8.2025 ]
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For the arithmetic sequence t1, t2, ... with common difference d=5 is s100 − s99 = 1000. Find the 101th term of this arithmetic sequence ( sn = the sum of the first n terms ) |
A. 1000 |
|---|---|
| B. 1005 | |
| C. 1010 | |
| D. 1500 | |
| E. less than 1000 |