Van een Rekenkundige Rij
t1, t2, ... met verschil  v = 5,
is   s100 − s99 = 1000.
De waarde van de term t101 is
A.   1000
B.   1005
C.   1010
D.   1500
E.   minder dan 1000
A    B    C    D    E

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Translation in   E N G L I S H

For the arithmetic sequence
t1, t2, ...   with common difference d=5
is   s100 − s99 = 1000.
Find the 101th term of this arithmetic sequence
( sn = the sum of the first n terms )
A.  1000
B.  1005
C.  1010
D.  1500
E.  less than 1000

Oplossing - Solution


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