Van een Rekenkundige Rij t1, t2, ... met verschil v = 5, is s100 − s99 = 1000. De waarde van de term t101 is |
A. 1000 |
---|---|
B. 1005 | |
C. 1010 | |
D. 1500 | |
E. minder dan 1000 |
[ 4,6-4275 - op net sinds 24.9.11-(E)-3.11.2023 ]
For the arithmetic sequence t1, t2, ... with common difference d=5 is s100 − s99 = 1000. Find the 101th term of this arithmetic sequence ( sn = the sum of the first n terms ) |
A. 1000 |
---|---|
B. 1005 | |
C. 1010 | |
D. 1500 | |
E. less than 1000 |