Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

De meetkundige rij $\sqrt 2, \sqrt 3, ... $ heeft als vierde term	A. $\large \frac {3} {2}\sqrt 2 $
	B. $\large \frac {3} {2}\sqrt 3 $
	C. $3 \sqrt 3 $
	D. $\sqrt 4$
	E. $\sqrt 5$

[ 4-4148 - op net sinds 5.6.09-(E)-27.10.2023 ]

Translation in E N G L I S H

What is the fourth term of the geometric sequence $\sqrt 2, \sqrt 3, ... $	A. $\large \frac {3} {2}\sqrt 2 $
	B. $\large \frac {3} {2}\sqrt 3 $
	C. $3 \sqrt 3 $
	D. $\sqrt 4$
	E. $\sqrt 5$

Oplossing - Solution

$\\ \text{De reden van de meetkundige rij is }\frac{\sqrt{3}}{\sqrt{2}}\\ \text{De vierde term is dus }\sqrt{2}\cdot\left ( \frac{\sqrt{3}}{\sqrt{2}} \right )^3=\sqrt{2}\cdot\frac{3\sqrt{3}}{2\sqrt{2}}=\frac 32 \sqrt3$

De meetkundige rij \(\sqrt 2, \sqrt 3, ... \) heeft als vierde term	A. \(\large \frac {3} {2}\sqrt 2 \)
	B. \(\large \frac {3} {2}\sqrt 3 \)
	C. \(3 \sqrt 3 \)
	D. \(\sqrt 4\)
	E. \(\sqrt 5\)

What is the fourth term of the geometric sequence \(\sqrt 2, \sqrt 3, ... \)	A. \(\large \frac {3} {2}\sqrt 2 \)
	B. \(\large \frac {3} {2}\sqrt 3 \)
	C. \(3 \sqrt 3 \)
	D. \(\sqrt 4\)
	E. \(\sqrt 5\)