Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

$\lim_{x \to \, 2}\, \frac{x^3-8}{x^2-4} =$	A. 1
	B. 2
	C. 3
	D. 4
	E. 0

[ 4-3941 - op net sinds 7.3.05-(E)-29.10.2023 ]

Translation in E N G L I S H

See above

Oplossing - Solution

$\\\lim_{x \to \, 2} \frac{x^3-8}{x^2-4} \!=\!\lim_{x \to \, 2} \frac {(x-2)(x^2+2x+4)} {(x-2)(x+2)} \!=\!\lim_{x \to \, 2} \frac {x^2+2x+4} {x+2}\! =\!\frac{4\!+\!4\!+\!4}{2+2} =\!\frac{12}{4}\!=\!3$