A.  \(\boldsymbol {\sqrt x} \)
B.  \(\boldsymbol {x^2}\)
C.  \(\large \boldsymbol {\frac {\sqrt x} {2}}\)
D.  \(\large \boldsymbol { \frac{\sqrt[4]{x}}{x}}\)
E.  \(\large \boldsymbol { \frac{\sqrt[4]{x^3}}{x}} \)
A    B    C    D    E

[ 4-3224 - op net sinds 9.11.14-(E)-30.10.2023 ]

Translation in   E N G L I S H

A.   \(\boldsymbol {\sqrt x} \)
B.   \(\boldsymbol {x^2}\)
C.   \(\large \boldsymbol {\frac {\sqrt x} {2}}\)
D.   \(\large \boldsymbol { \frac{\sqrt[4]{x}}{x}}\)
E.   \(\large \boldsymbol { \frac{\sqrt[4]{x^3}}{x}} \)

Oplossing - Solution

\(\small\sqrt[4]{81}=3\quad want \quad 3.3.3.3=81 \quad maar\; ook: \sqrt[4]{81}=\sqrt{\sqrt{81}}=\sqrt{9}=3 \)
1ste manier :
\(\large \frac{1}{\sqrt{\sqrt{x}}}=\frac{1}{\sqrt[4]{x}}=\frac{\sqrt[4]{x^3}}{\sqrt[4]{x}.\sqrt[4]{x^3}}= \frac{\sqrt[4]{x^3}}{\sqrt[4]{x^4}}=\frac{\sqrt[4]{x^3}}{x} \)
2de manier :
\(\large \frac{1}{\sqrt{\sqrt{x}}}=\frac{1.\sqrt{\sqrt{x}}}{\sqrt{\sqrt{x}}.\sqrt{\sqrt{x}}}=\frac{\sqrt{\sqrt{x}}}{\sqrt x}= \frac{\sqrt{\sqrt{x}}.\sqrt x}{\sqrt x.\sqrt x}=\frac{\sqrt[4]{x}.\sqrt[4]{x^2}}{x}=\frac{\sqrt[4]{x^3}}{x} \)
gricha