\(\displaystyle\lim_{x\to+\infty}\left(\frac{x\,-\,3}{x}\right)^{\frac x2}=\lim_{x\to+\infty}\left(1+\frac{3}{-x}\right)^{\frac x2}=\lim_{x\to+\infty}\left(1+\frac{3}{-x}\right)^{\frac{-x}{3}.\frac{-x}{2}}\\=\!\!\displaystyle\lim_{x\to+\infty}\left(\left(1+\frac{3}{-x}\right)^{\frac{-x}{3}}\right)^{-\frac32}\!\!=\left(\lim_{x\to+\infty}\left(1+\frac{3}{-x}\right)^{\frac{-x}{3}}\right)^{-\frac32}\!\!=e^{-\frac32}\!\!=e^{-1,5}=\frac{1}{e\sqrt e}\)
gricha - v2680 - 25.4.2026