sin2 α  = A.  \(\boldsymbol{1+\cot^2\alpha}\)
B.  \(\boldsymbol{1+\cos^2\alpha}\)
C.  \(\boldsymbol{1+\tan^2\alpha}\)
D.  \(\large\boldsymbol{\frac {1} {1\,+\:\tan^2\alpha} }\)
E.  \(\large\boldsymbol{\frac {1} {1\,+\:\cot^2\alpha} }\)
A    B    C    D    E

[ 4-2654 - op net sinds 7.11.12-(E)-30.10.2023 ]

Translation in   E N G L I S H

see above

Oplossing - Solution

\(\sin^2 \alpha = \frac {1} {1+ \cot^2 \alpha } \) want
sin² α . (1 + cot² α) = sin² α + sin² α.cot² α = sin² α + cos² α = 1
gricha