Welke uitspraak(vorm)    is  WAAR ?
A.   x² – 1 = 0  ⇔  x = 1  ∧  x = –1
B.   x² – 1 = 0  ⇔  x = 1
C.   x² – 1 = 0  ⇔  x = 1  ∨  x = –1
D.   x² – 1 = 0  ⇔  x = –1
E.   x² – 1 = 0  ⇔  1 = –x²
    A    B    C    D    E

[ 3,4-2485 - op net sinds 21.9.2025-(E)-23.9.2025 ]

Translation in   E N G L I S H

IN CONSTRUCTION

Oplossing - Solution

x² – 1 = 0  ⇔  (x − 1)(x + 1) = 0  ⇔  x − 1 = 0  ∨  x + 1 = 0  ⇔  x = 1 ∨ x = −1
GWB