Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

De onbepaalde integraal $https://latex.codecogs.com/png.image?\dpi{110}\int \frac{1}{\sin^2(3x+1)}\: dx$ is gelijk aan	A. $\boldsymbol{-\,\frac {1} {3}\cot\,(3x+1) + C} $
	B. $\boldsymbol{ \frac {1} {3} \cot\,(3x+1)+ C}$
	C. $\boldsymbol{ \frac {1} {3}\tan\,(3x+1) + C} $
	D. $\boldsymbol{-\,\frac {1} {3}\tan\,(3x+1) + C} $
	E. $\boldsymbol{-3\cot\,(3x+1)+ C }$

[ 6-2475 - op net sinds 8.6.2020-()-16.6.2024 ]

$\int\frac{1}{\sin^2(3x+1)}dx=\frac 13\int\frac{1}{\sin^2(3x+1)}d(3x+1)=-\frac13\cot(3x+1)+C$

De onbepaalde integraal $https://latex.codecogs.com/png.image?\dpi{110}\int \frac{1}{\sin^2(3x+1)}\: dx$ is gelijk aan	A. \(\boldsymbol{-\,\frac {1} {3}\cot\,(3x+1) + C} \)
	B. \(\boldsymbol{ \frac {1} {3} \cot\,(3x+1)+ C}\)
	C. \(\boldsymbol{ \frac {1} {3}\tan\,(3x+1) + C} \)
	D. \(\boldsymbol{-\,\frac {1} {3}\tan\,(3x+1) + C} \)
	E. \(\boldsymbol{-3\cot\,(3x+1)+ C }\)