Wat is correct ?
A.  \(\boldsymbol{\text{Als }\;x+\frac1x = y \; \text{ dan is }\; x^2+\frac{1}{x^2}=y^2-2 }\)
B.  \(\boldsymbol{\text{Als }\;x+\frac1x = y \; \text{ dan is }\; x^2+\frac{1}{x^2}=y^2+2 }\)
C.  \(\boldsymbol{\text{Als }\;x+\frac1x = y \; \text{ dan is }\; x^2+\frac{1}{x^2}=y^2 }\)
D.  \(\boldsymbol{\text{Als }\;x-\frac1x = y \; \text{ dan is }\; x^2-\frac{1}{x^2}=y^2+2 }\)
E.  \(\boldsymbol{\text{Als }\;x-\frac1x = y \; \text{ dan is }\; x^2-\frac{1}{x^2}=y^2-2 }\)
A    B    C    D   E

[ 4-2300 - op net sinds 1.3.00-(E)-10.12.2023 ]

Translation in   E N G L I S H

What is correct ?
A.   \(\small\boldsymbol{\text{If }\;x+\frac1x = y \; \text{ then }\; x^2+\frac{1}{x^2}=y^2-2 }\)
B.   \(\small\boldsymbol{\text{If }\;x+\frac1x = y \; \text{ then }\; x^2+\frac{1}{x^2}=y^2+2 }\)
C.   \(\small\boldsymbol{\text{If }\;x+\frac1x = y \; \text{ then }\; x^2+\frac{1}{x^2}=y^2 }\)
D.   \(\small\boldsymbol{\text{If }\;x-\frac1x = y \; \text{ then }\; x^2-\frac{1}{x^2}=y^2+2 }\)
E.   \(\small\boldsymbol{\text{If }\;x-\frac1x = y \; \text{ then }\; x^2-\frac{1}{x^2}=y^2-2 }\)

Oplossing - Solution


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