Discriminant D :
D = 4(2a + 3b)² − 4.24ab = 4(4a² + 12ab + 9b² − 24ab)
= 4(4a² − 12ab + 9b²) = 4(2a − 3b)²
x1 =
(4a + 6b + 4a − 6b) = (8a) = 4ax2 =
(4a + 6b − 4a + 6b) = (12b) = 6b|
Eén van de oplossingen van
de vergelijking (x onbekende) x2 − 2 (2a + 3b)x + 24ab = 0 is |
A. 6b |
|---|---|
| B. − 6b | |
| C. − 4a | |
| D. 4a + 6b | |
| E. − 4a − 6b |
[ 4-2196 - op net sinds 24.7.2020-(E)-2.11.2024 ]
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One of the solutions of the equation (x unknown) x2 − 2 (2a + 3b)x + 24ab = 0 is |
|---|
(4a + 6b + 4a − 6b) = (8a) = 4a(4a + 6b − 4a + 6b) = (12b) = 6b