Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

$https://latex.codecogs.com/png.image?\dpi{110}\frac 6x - x \: < \: 1$ is gelijkwaardig met	A. $\large\boldsymbol{\frac {x^2\,-\:x\:+\:6} {x} }< 0 $
	B. $\large\boldsymbol{\frac {(x-3)(x+2)}{x}} < 0 $
	C. $\large\boldsymbol{\frac {(x-3)(x-2)}{x}} < 0 $
	D. $\large\boldsymbol{\frac {(x-2)(x+3)}{x}} > 0 $
	E. $\boldsymbol{6 - x^2 - x < 0 }$

[ 4,5-2103 - op net sinds 27.12.15-()-2.11.2023 ]

6/x − x < 1
⇔ 6/x − x − 1 < 0
⇔ 6/x − x²/x − x/x < 0
⇔ (6 − x² − x) / x < 0
⇔ (x² + x − 6) / x > 0
⇔ (x − 2).(x + 3) / x > 0

$https://latex.codecogs.com/png.image?\dpi{110}\frac 6x - x \: < \: 1$ is gelijkwaardig met	A. \(\large\boldsymbol{\frac {x^2\,-\:x\:+\:6} {x} }< 0 \)
	B. \(\large\boldsymbol{\frac {(x-3)(x+2)}{x}} < 0 \)
	C. \(\large\boldsymbol{\frac {(x-3)(x-2)}{x}} < 0 \)
	D. \(\large\boldsymbol{\frac {(x-2)(x+3)}{x}} > 0 \)
	E. \(\boldsymbol{6 - x^2 - x < 0 }\)