Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

Welke driehoek waarvan hier de zijden gegeven zijn (in m), is rechthoekig ?	A.	$https://latex.codecogs.com/png.image?\dpi{110}\begin{matrix}10 & \circledast & 10 & \circledast & 14 \\ \\2-\sqrt 2 & \circledast& 2+\sqrt 2 & \circledast & \sqrt{10} \\ \\\frac 13 & \circledast & \frac 14 & \circledast & \frac 15 \\ \\\sqrt {22} & \circledast & \sqrt 2 - 3 & \circledast & \sqrt 2 + 3 \\ \\9 & \circledast & 16 & \circledast & 25 \\\end{matrix}$
B.
C.
D.
E.

The measures of the sides of a triangle are given. Which triangle is right/rectangle ?	A.	$https://latex.codecogs.com/png.image?\dpi{110}\begin{matrix}10 & \circledast & 10 & \circledast & 14 \\ \\2-\sqrt 2 & \circledast& 2+\sqrt 2 & \circledast & \sqrt{10} \\ \\\frac 13 & \circledast & \frac 14 & \circledast & \frac 15 \\ \\\sqrt {22} & \circledast & \sqrt 2 - 3 & \circledast & \sqrt 2 + 3 \\ \\9 & \circledast & 16 & \circledast & 25 \\\end{matrix}$
	B.
	C.
	D.
	E.

Het volstaat te controleren of het kwadraat van de langste zijde gelijk is aan de som van de kwadraten van de twee andere zijden
$https://latex.codecogs.com/png.image?\dpi{110}A.\to 14^2=196 \qquad 10^2+10^2\neq 196$
$https://latex.codecogs.com/png.image?\dpi{110}B.\to (\sqrt{10})^2=10\\{\color{Green} .}\qquad (2-\sqrt2))^2=4-4\sqrt2+2=6-4\sqrt 2\\{\color{Green} .}\qquad (2+\sqrt 2)^2=4+4\sqrt2+2=6+4\sqrt2 \\{\color{Green} .}\qquad \(6-4\sqrt 2)+(6+4\sqrt 2)=12\neq 10$
$https://latex.codecogs.com/png.image?\dpi{110}C.\left ( \frac13 \right )^2=\frac19\qquad \left ( \frac14 \right )^2=\frac1{16}\qquad\left ( \frac15 \right )=\frac{1}{25}\\{\color{Green} .}\qquad\quad maar\quad \frac19\neq \frac1{16}+\frac1{25}$
$https://latex.codecogs.com/png.image?\dpi{110}D.\to (\sqrt{22})^2=22 \\{\color{Green} .}\qquad (\sqrt2+3)^2=2+6\sqrt2+9=11+6\sqrt2\\{\color{Green} .}\qquad (\sqrt2-3)^2=2-6\sqrt2+9=11-6\sqrt2\\{\color{Green} .}\qquad (11+6\sqrt2)+(11-6\sqrt2)=22$
$https://latex.codecogs.com/png.image?\dpi{110}E.\to 25^2=625 \qquad 16^2+9^2=256+81=337\neq 625$