\(\small\sqrt 2\cdot \sqrt 2\cdot \sqrt 2 =\sqrt 2 +\sqrt 2\\\small\sqrt 2\cdot \sqrt 2\cdot \sqrt 2 = \sqrt 2 +\sqrt 2 + \sqrt 2\\ \small\sqrt 3\cdot \sqrt 3\cdot \sqrt 3 = \sqrt 3 + \sqrt 3 + \sqrt 3\)

Van deze drie gelijkheden 		A.   is er precies één van juist
B.   is enkel de eerste en de tweede juist
C.   is enkel de eerste en de derde juist
D.   is enkel de tweede en de derde juist
E.   is er geen enkele juist
A    B    C    D    E

[ 3-1184 - op net sinds 27.2.13-(E)-1.9.2025 ]

Translation in   E N G L I S H

\(\small\sqrt 2\cdot \sqrt 2\cdot \sqrt 2 =\sqrt 2 +\sqrt 2\\\small\sqrt 2\cdot \sqrt 2\cdot \sqrt 2 = \sqrt 2 +\sqrt 2 + \sqrt 2\\ \small\sqrt 3\cdot \sqrt 3\cdot \sqrt 3 = \sqrt 3 + \sqrt 3 + \sqrt 3\)
 A.  only one equality is true
B.  only true : 1st and 2nd
C.  only true : 1st and 3th
D.  only true : 2nd and 3th
E.  none of these

Oplossing - Solution

\(\sqrt{2}.\sqrt{2}.\sqrt{2} = (\sqrt{2}.\sqrt{2}).\sqrt{2}=2\sqrt{2} =\sqrt{2} +\sqrt{2} \\ \sqrt{3}.\sqrt{3}.\sqrt{3} = (\sqrt{3}.\sqrt{3}).\sqrt{3} =3\sqrt{3}\\ \sqrt{3}+\sqrt{3}+\sqrt{3} = 3\sqrt{3}\)
gricha