Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

$https://latex.codecogs.com/png.image?\dpi{110}\frac{\cos\, (90^\circ+\alpha )}{\tan(180^\circ -\alpha )}=$	A. $\boldsymbol{-1 }$
	B. $\boldsymbol{\cos \alpha}$
	C. $\boldsymbol{-\,\cos \alpha }$
	D. $\boldsymbol{\large \frac {1} {\cos \alpha} }$
	E. $\boldsymbol{-\,\large\frac {1} {\cos \alpha} }$

[ 4-0757 - op net sinds 26.11.97-(E)-3.11.2023 ]

Translation in E N G L I S H

See above

Oplossing - Solution

$https://latex.codecogs.com/png.image?\dpi{110}\frac{\cos\, (90^\circ+\alpha )}{\tan(180^\circ\!-\!\alpha )}=\frac{\sin[90^\circ\!-\!(90^\circ\!+\!\alpha )]}{-\tan \alpha}=\frac{\sin(90^\circ\!-\!90^\circ\!-\!\alpha )}{-\tan\alpha }=\frac{\sin(-\alpha )}{-\frac{\sin\alpha }{\cos\alpha }} =...$

$https://latex.codecogs.com/png.image?\dpi{110}\frac{\cos\, (90^\circ+\alpha )}{\tan(180^\circ -\alpha )}=$	A. \(\boldsymbol{-1 }\)
	B. \(\boldsymbol{\cos \alpha}\)
	C. \(\boldsymbol{-\,\cos \alpha }\)
	D. \(\boldsymbol{\large \frac {1} {\cos \alpha} }\)
	E. \(\boldsymbol{-\,\large\frac {1} {\cos \alpha} }\)