Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

$D\: \frac{7}{3\, (2-3x)}=$	A. $\large\boldsymbol{\frac {7} {\sqrt{2\,-\,3x}} }$
	B. $\large\boldsymbol{\small -\large \,\frac {7} {(2\,-\,3x)^2} }$
	C. $\large\boldsymbol{\frac {7} {(3x\,-\,2)^2} }$
	D. $\boldsymbol{-\,\large\frac {7} {3(2\,-\,3x)^2} }$
	E. $\large\boldsymbol{0 }$

[ 6-0614 - op net sinds 7.7.07-(E)-30.10.2023 ]

Translation in E N G L I S H

See above

Oplossing - Solution

$D\; \frac{7}{3.(2-3x)}=\frac73.D\frac{1}{2-3x} =\frac73\cdot \left ( -\frac{1}{(2-3x)^2} \right )\cdot D(2-3x) =\frac{7}{(2-3x)^2}=\frac{7}{(3x-2)^2}$
Vergeet niet dat (a − b)² = (b − a)² ! !

$D\: \frac{7}{3\, (2-3x)}=$	A. \(\large\boldsymbol{\frac {7} {\sqrt{2\,-\,3x}} }\)
	B. \(\large\boldsymbol{\small -\large \,\frac {7} {(2\,-\,3x)^2} }\)
	C. \(\large\boldsymbol{\frac {7} {(3x\,-\,2)^2} }\)
	D. \(\boldsymbol{-\,\large\frac {7} {3(2\,-\,3x)^2} }\)
	E. \(\large\boldsymbol{0 }\)