Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

$\frac{cot\: (-\alpha +5\pi )}{\cot\: (\frac{\pi }{2}+\alpha )}=$	A. tan²α
	B. − tan²α
	C. cot²α
	D. − cot²α
	E. geen van de vorige

[ 5-0558 - op net sinds 8.11.12-(E)-21.11.2024 ]

Translation in E N G L I S H

$\frac{cot\: (-\alpha +5\pi )}{\cot\: (\frac{\pi }{2}+\alpha )}$ is equal to	A. tan²α
	B. − tan²α
	C. cot²α
	D. − cot²α
	E. none of the above

Oplossing - Solution

${\color{Cyan} \mid } \newline {\color{DarkGreen} \frac{cot\: (-\alpha +5\pi )}{cot\: (\frac{\pi }{2}+\alpha )}= \frac{cot\: (\pi -\alpha )}{tan\left [ \frac{\pi }{2}-\left ( \frac{\pi }{2}+\alpha \right ) \right ]}= \frac{-cot\: \alpha }{tan(-\alpha )}= \frac{cot\: \alpha }{tan\: \alpha }=\cdots$