Wiskunde Multiple Choice Vraag

$\frac{\cot(\pi+x)\cdot\sin\left(\frac{\pi}{2}-x\right)}{\tan(-x)\cdot\cos(\pi-x)}=$	A. 1
	B. −1
	C. cot x
	D. tan² x
	E. cot² x
	F. − cos x
	G. cos² x

[ 5-5675 - op net sinds 18.12.2025-(E)- ]

See above

$\frac{\cot(\pi+x)\cdot\sin\left(\frac{\pi}{2}-x\right)}{\tan(-x)\cdot\cos(\pi-x)}=\frac{\cot x\cdot\cos x}{-\tan x\,\cdot(-\cos x)}=\cot^2x$