Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

$https://latex.codecogs.com/png.image?\dpi{110}0,25^{-\frac{\pi}{2}}=$	A. $https://latex.codecogs.com/png.image?\dpi{110}0,5^{\pi}$
	B. $https://latex.codecogs.com/png.image?\dpi{110}2^{\pi}$
	C. $https://latex.codecogs.com/png.image?\dpi{110}-0,5^{\pi}$
	D. $https://latex.codecogs.com/png.image?\dpi{110}4^{- \frac{2}{\pi}$
	E. $https://latex.codecogs.com/png.image?\dpi{110}5^{- \pi}$

[ 6-7678 - op net sinds 29.5.15-(E)-25.8.2025 ]

Translation in E N G L I S H

$https://latex.codecogs.com/png.image?\dpi{110}0,25^{-\frac{\pi}{2}}=$	A. $https://latex.codecogs.com/png.image?\dpi{110}0,5^{\pi}$
	B. $https://latex.codecogs.com/png.image?\dpi{110}2^{\pi}$
	C. $https://latex.codecogs.com/png.image?\dpi{110}-0.5^{\pi}$
	D. $https://latex.codecogs.com/png.image?\dpi{110}4^{- \frac{2}{\pi}$
	E. $https://latex.codecogs.com/png.image?\dpi{110}5^{- \pi}$

Oplossing - Solution

$\\ \text {Gebruik liefst de regel :}\\ \left ( \frac ab \right )^n=\left ( \frac ba \right )^{-n} \\ 0,25^{-\frac{\pi }{2}}=4^\frac{\pi }{^2}=(2^2)^\frac{\pi }{^2}=2^\pi$
$\\ \text {Gebruik liefst de regel :}\\ \left ( \frac ab \right )^n=\left ( \frac ba \right )^{-n} \\ 0,25^{-\frac{\pi }{2}}=4^\frac{\pi }{^2}=(2^2)^\frac{\pi }{^2}=2^\pi$